53

I have some junit tests which create some resources which should also be closed.

One way to implement this logic is using the @Before and @After approach.

What I did was to encapsulate the creation in some utility class to be reused. For example:

class UserCreatorTestUtil implements AutoClosable {
  User create() {...}
  void close() {...}
}

The whole point is for the object to close itself, rather than needing to remember to close it in @After.

The usage should be:

@Test
void test() {
  try (UserCreatorTestUtil userCreatorTestUtil = new UserCreatorTestUtil()) {
    User user = userCreatorTestUtil.create();
    // Do some stuff regarding the user's phone
    Assert.assertEquals("123456789", user.getPhone());
  }
}

The problem is that junit's assert keyword throws an Error - not Exception.

Will the try-with-resource "catch" the Error and invoke the close method?

* Couldn't find the answer in the try-with-resources documentation.


  • OT: Just for the records: "I have some junit tests which create some resources" so you don't have UnitTests, what you have are Module Tests using a UnitTest - Framework. - Timothy Truckle
  • @TimothyTruckle - while picking nits: some resource may just as well refer to a mocked out version, that still must be closed for everything to make sense. - Martin Ba
  • Both Errors and Exceptions (uppercase E) are kinds of exceptions (lowercase e). - immibis
  • @immibis but we can call them Throwables to be case-insensitive and unambigious. - Thilo
  • @Thilo But case-insensitive languages are literally Satan. - immibis

5 답변


74

It does not catch anything. But it does finally close all resources.

finally blocks are run even when an Error is thrown.


  • No, it simply doesn't know about any exceptions/errors. - Stephan Bijzitter
  • Yes, it does its cleanup in the same way a manual finally block would do. - Thilo
  • Note that finally works well except for System.exit(): stackoverflow.com/questions/14905006/… - Christophe Roussy
  • It behaves almost like a finally block, as, unlike a finally block, it will catch all subsequent Throwables of the close() operations and add them as suppressed throwable to the primary throwable. A finally block can’t do that as it has no knowledage about the primary throwable, if there is one. - Holger
  • @Holger: Well, it is implemented as a finally block in addition to a catch block that does not really catch anything (just records the primary throwable and rethrows). All the "action" happens in the finally block. See @Nicolas answer for details. - Thilo

37

The pseudo-code of a basic try-with-resources statement is (cf Java Language Specification §14.20.3.1):

final VariableModifiers_minus_final R Identifier = Expression;
Throwable #primaryExc = null;

try ResourceSpecification_tail
    Block
catch (Throwable #t) {
    #primaryExc = #t;
    throw #t;
} finally {
    if (Identifier != null) {
        if (#primaryExc != null) {
            try {
                Identifier.close();
            } catch (Throwable #suppressedExc) {
                #primaryExc.addSuppressed(#suppressedExc);
            }
        } else {
            Identifier.close();
        }
    }
}

As you can see it catches Throwable not Exception which includes Error but only to get the primary exception in order to add as suppressed exceptions any exceptions that occurred while closing the resources.

You can also notice that your resources are closed in the finally block which means that they will be closed whatever happens (except in case of a System.exit of course as it terminates the currently running Java Virtual Machine) even in case an Error or any sub class of Throwable is thrown.


  • Unfortunately, javac adheres literally to this convoluted formal specification. Considering, that finally is eventually implemented via code duplication for the two cases, it makes no sense at all, to store the exception in a variable and test it against null, when it is already implied by the code path whether there is an exception or not… - Holger
  • @Holger: Whether there was an exception or not is not implied by the code path. Remember that the finally block is executed whether there was an exception or not. What code duplication do you mean (I guess the two Identifier.close()) and why does it annoy you? What would you suggest try-with-resources should do instead? - siegi
  • @siegi: on the byte code level, there is no finally feature, hence, a finally block is compiled by copying the action to every code path that could leave the block, plus an exception handler, i.e. try { foo(); } finally { bar(); } gets compiled to try { foo(); } catch(Throwable t) { bar(); throw t; } bar();, duplicating the bar() invocation code. There, it is implied by the code path whether an exception occurred or not, i.e. the first bar(); invocation is the one under exceptional condition, the second is the one without. - Holger
  • @siegi: The code produced by javac as a consequence of this is discussed in this question. In my answer there, I referred to this behavior as “an artifact of how javac works internally”, without naming “implements this like a finally block” directly, simply because I didn’t know that formal specification at this point, but seeing it now, things become entirely clear (and the general statement still holds). - Holger
  • @Holger: Oh, I thought about code duplication at the Java language level (i.e. the snipped above) and not at the bytecode level. I guess it was a design decision to have no special case handling for try-with-resources in javac but to simply "desugar" it according to the language specification and then let the JIT compiler do its job. - siegi

13

Try-with-resources don't catch anything in and of themselves.

However, you can attach a catch block to the end of the try-with-resources block, to catch whatever types of Throwable you like:

try (UserCreatorTestUtil userCreatorTestUtil = new UserCreatorTestUtil()) {
  // ... Whatever
} catch (RuntimeException e) {
  // Handle e.
} catch (Exception | Throwable t) {
  // Handle t.
}


9

The idea behind try-with-resources is to make sure that the resources should be closed.

The problem with conventional try-catch-finally statements is that let's suppose your try block throws an exception; now usually you'll handle that exception in finally block.

Now suppose an exception occurs in finally block as well. In such a case, the exception thrown by try catch is lost and the exception generated in finally block gets propagated.

try {
    // use something that's using resource
    // e.g., streams
} catch(IOException e) {
   // handle 
} finally {
    stream.close();
    //if any exception occurs in the above line, than that exception
    //will be propagated and the original exception that occurred
    //in try block is lost.
}

In try-with-resources the close() method of the resource will get automatically called, and if the close() throws any exception, the rest of the finally isn't reached, and the original exception is lost.

Contrast that with this:

try (InputStream inputStream= new FileInputStream("C://test.txt")){
    // ... use stream
} catch(IOException e) {
   // handle exception
}

in the above code snippet, the close() method automatically gets called and if that close() method also generated any exception, than that exception will automatically get suppressed.

See also: Java Language Specification 14.20.3


5

Misconception on your end: try-with-resources does not do a catch.

It does a final finally, therefore the kind of "problem" doesn't matter.

See the JLS for further information!


  • But it does do a catch, so that it can preserve the original exception, if any, and add subsequent exceptions as suppressed exceptions. - Mark Rotteveel

Linked


Related

Latest