Comparing string array to variable Java [duplicate]

1

This question already has an answer here:

I have a dilemma I am trying to find out the best way to compare a string variable called (code) to an array of strings. if it equal it i want it to break the for loop. Which would should I select. I think the 2nd one will work but the 1st one seems like it would and its simpler. Any advice would be appreciated. 

String[] badcodes = {"8QQ", "8BQ", "8JQ"};
if (code.equals(badcodes)) {
    break;
}

String[] badcodess = {"8QQ", "8BQ", "8JQ"};
for (String s : badcodess) {

    if (s.equals(code)) {
        break; // break out of for loop
    }
}

--------------based on answer ----------------------

  String[] badcodes = {"8QQ", "8BQ", "8JQ"};
    boolean check = Arrays.asList(badcodess).contains(code);
    if (check = true){
    // do something
    }else{
     do something
     }
Jonathan

출처 java arrays string foreach
  • You mean, if any of the strings in the array equals the value of code? - Federico klez Culloca
  • "compare a string variable called (code) to an array of strings" A String will never be equal to a String[] - csmckelvey
  • Yes that is correct thanks - Jonathan

2 답변

2

You can convert your array to a List then use List::contains to check if the list contain the code or not :

boolean check = Arrays.asList(badcodess).contains(code);

  • I wrote some code above I want to use an if statement, would that work ? since check in boolean i am checking if it is true or not correct? - Jonathan
  • @Jonathan you can just use if (check){//do something}else{//do something else} no need to use check = true this is an assignment and not comparing, to check if a check equals to true or not you need to use double equal - YCF_L
  • so your saying I dont have to write check = true ? - Jonathan
  • exactly just use if(check) it equivalent to if(check == true) - YCF_L
  • OKAY I see if it contain the code do this if not do this check = true is not needed because if it equals true your going to do something anyway... I see i got it - Jonathan
2

Your first option would not do what you expect to do. And even if someArray.equals(anotherArray) would do an element-wise comparison (which it doesn't) - you would need to have the special array contain all objects of the existing array, in the exact same order. In that sense: first understand why this approach is flawed in many ways, to then drop it.

The second option is fine, but if you really want to "improve" the whole thing - use ArrayList instead - which has a contains() method.

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